In the previous section we have discussed about length of an arc calculator and In today's session we are going to discuss about Straight line, It was developed by mathematicians to represent objects which are straight and have insignificant depth and width. They have one dimension that is only length with no depth and width .The straight line definition says it is nothing only flow of points and it is equally extended to the two points
A line was described by Euclid as breathless length and with some provable properties he constructed geometry which is called as Euclidean Geometry in today’s Mathematics .A line is called as shortest path between the points but some mathematicians says that a line is a 2 dimensional Vector space
Equation of a Straight line or slope intercepts form
Y=mx +b
Where
Y=how far
X =how far along
M=slope
B= Y intercept
The equation has variable expression without any exponents
Find the equation of straight line which has slope m = 3
and passes through point (2, –6).
Solu: So in the above problem value of the slope is m=3.And the value of x = 2, and value of y =-6.We don’t have the value of b in the equation
Here we will put the values in the slope equation to get the value of b
y=mx + b
(-6)=3*(2) + b
-6 = 6+b
-12=b
So equation of the line will be y= 3x-12
Find the equation of straight line which has slope m = 6
and passes through point (-1, –3).
Solution: So in the above problem value of the slope is m=6.And the value of x = -1, and value of y =-3.We don’t have the value of b in the equation
Here we will put the values in the slope equation to get the value of b
y=mx + b
(-3)=6*(-1) + b
-3 = -6+b
3=b
So equation of the line will be y= 6x+3
For square root calculator and syllabus of CBSE books for class 9 visit Online portals.
A line was described by Euclid as breathless length and with some provable properties he constructed geometry which is called as Euclidean Geometry in today’s Mathematics .A line is called as shortest path between the points but some mathematicians says that a line is a 2 dimensional Vector space
Equation of a Straight line or slope intercepts form
Y=mx +b
Where
Y=how far
X =how far along
M=slope
B= Y intercept
The equation has variable expression without any exponents
Find the equation of straight line which has slope m = 3
and passes through point (2, –6).
Solu: So in the above problem value of the slope is m=3.And the value of x = 2, and value of y =-6.We don’t have the value of b in the equation
Here we will put the values in the slope equation to get the value of b
y=mx + b
(-6)=3*(2) + b
-6 = 6+b
-12=b
So equation of the line will be y= 3x-12
Find the equation of straight line which has slope m = 6
and passes through point (-1, –3).
Solution: So in the above problem value of the slope is m=6.And the value of x = -1, and value of y =-3.We don’t have the value of b in the equation
Here we will put the values in the slope equation to get the value of b
y=mx + b
(-3)=6*(-1) + b
-3 = -6+b
3=b
So equation of the line will be y= 6x+3
For square root calculator and syllabus of CBSE books for class 9 visit Online portals.
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