In the mathematics we study a lot of concepts which are related to our daily life. These concepts help to solve the problems related to mathematical calculations. In the mathematical field there are many ways to represent the things in the measurable quantity. These measurable quantities provide an easy and convenient way to represent the things, which help in to performing the various tasks related to our daily routine life.
Here we are going to discuss about the rate and distance in geometry. Rate contains the collection of several measurable quantity or measures to specify the quantity of the product or things. In simple terms rates is a ratio, which demonstrates the relationship of a thing to the measurable quantity.
Suppose John makes a trip to Hollywood, in which he covers a distance of 250 miles in 5 hours then what is the speed of his car?
This would be represented by dividing the distance by the time.
Let’s see 250/5 = 50 miles per hour
It means john covers the distance at the rate of 50miles/hour. Here ( / )symbol represent ‘ at per’.
Now we show the relationship between rate and distance. As we describe rate termed as ratio, which represents the comparison of two different numbers to display them in measurable quantity.
Now we will see an example to represent the relationship between the rate and distance:
Example: Suppose there is a shop where jack purchases 5 liter milk. Now he pays $15 for the milk. So find the amount of 1 liter milk.
Solution: Here given that purchase milk = 5 liter
Paid amount = $ 15
So, amount of 1 liter = $15 / 5
= $3/liter
In the next session we are going to discuss time and angle measures
Here we are going to discuss about the rate and distance in geometry. Rate contains the collection of several measurable quantity or measures to specify the quantity of the product or things. In simple terms rates is a ratio, which demonstrates the relationship of a thing to the measurable quantity.
Suppose John makes a trip to Hollywood, in which he covers a distance of 250 miles in 5 hours then what is the speed of his car?
This would be represented by dividing the distance by the time.
Let’s see 250/5 = 50 miles per hour
It means john covers the distance at the rate of 50miles/hour. Here ( / )symbol represent ‘ at per’.
Now we show the relationship between rate and distance. As we describe rate termed as ratio, which represents the comparison of two different numbers to display them in measurable quantity.
Now we will see an example to represent the relationship between the rate and distance:
Example: Suppose there is a shop where jack purchases 5 liter milk. Now he pays $15 for the milk. So find the amount of 1 liter milk.
Solution: Here given that purchase milk = 5 liter
Paid amount = $ 15
So, amount of 1 liter = $15 / 5
= $3/liter
In the next session we are going to discuss time and angle measures
No comments:
Post a Comment